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question 62
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reduce the following to its lowest terms
16/80 = x/y
solve for x in the above question;
solve for y in the above question:
question 63
not yet answered
marked out of 1.00
flag question
reduce the following to its lowest terms
125/400 = x/y
solve for x in the above question;
solve for y in the above question:

Explanation:

Question 62

Step1: Find GCD of 16 and 80

The greatest common divisor (GCD) of 16 and 80 is 16.

Step2: Divide numerator and denominator by GCD

Divide 16 by 16: $16 \div 16 = 1$
Divide 80 by 16: $80 \div 16 = 5$
So, $\frac{16}{80}=\frac{1}{5}$, which means $x = 1$ and $y = 5$.

Step1: Find GCD of 125 and 400

The GCD of 125 and 400 is 25.

Step2: Divide numerator and denominator by GCD

Divide 125 by 25: $125 \div 25 = 5$
Divide 400 by 25: $400 \div 25 = 16$
So, $\frac{125}{400}=\frac{5}{16}$, which means $x = 5$ and $y = 16$.

Answer:

Solve for X: 1
Solve for Y: 5

Question 63