Question

question 37 of 40
solve the system of equations.
$4x - 3y = 12$
$3x + 6y = 42$
a. $(6, 4)$
b. $(3, 0)$
c. $(9, 8)$
d. $(8, 3)$

Explanation:

Step1: Eliminate y term

Multiply first equation by 2: $8x - 6y = 24$. Add to second equation: $(8x - 6y) + (3x + 6y) = 24 + 42$ → $11x = 66$.

Step2: Solve for x

$x = \frac{66}{11} = 6$.

Step3: Find y using x=6

Substitute x=6 into first equation: $4(6) - 3y = 12$ → $24 - 3y = 12$ → $-3y = -12$ → $y=4$.

Answer:

A. (6,4)