Question

question 25
what is an equation of the line that passes through the point (-4, -1) and is parallel to the line x + y = 0?

Explanation:

Step1: Find the slope of the given line

The line $x + y=0$ can be rewritten as $y=-x$, so its slope $m=- 1$. Parallel lines have the same slope, so the slope of the required line is also $m = - 1$.

Step2: Use the point - slope form

The point - slope form of a line is $y - y_1=m(x - x_1)$, where $(x_1,y_1)=(-4,-1)$ and $m=-1$. Substitute these values into the formula: $y-(-1)=-1\times(x - (-4))$.

Step3: Simplify the equation

$y + 1=-(x + 4)$, expand to get $y+1=-x - 4$, and then rewrite it in the general form $x + y+5 = 0$.

Answer:

$x + y+5 = 0$