Question

question 2 of 25
what is the center of the circle given by the equation $(x - 3)^2+(y - 9)^2=16$?
a. $(-3,-9)$
b. $(-9,-3)$
c. $(3,9)$
d. $(9,3)$

Explanation:

Step1: Recall the standard form of a circle equation

The standard form of a circle equation is \((x - h)^2+(y - k)^2=r^2\), where \((h,k)\) is the center of the circle.

Step2: Identify \(h\) and \(k\)

For the given equation \((x - 3)^2+(y - 9)^2 = 16\), comparing with \((x - h)^2+(y - k)^2=r^2\), we have \(h = 3\) and \(k=9\). So the center of the circle is \((3,9)\).

Answer:

C. (3, 9)