Question

question 21 points 2

find \\((0.2)a\\) for \\(a = \

$$\begin{bmatrix} -3 & 4 & 5 \\\\ 1 & -2 & 3 \\\\ 7 & 8 & 9 \\\\ -5 & 6 & -7 \\end{bmatrix}$$

\\)

\\(\circ \

$$\begin{bmatrix} 0.6 & -0.8 & -1 \\\\ -0.2 & 0.4 & -0.6 \\\\ -1.4 & -1.6 & -1.8 \\\\ 1 & -1.2 & 1.4 \\end{bmatrix}$$

\\)

\\(\circ \

$$\begin{bmatrix} -0.6 & 0.8 & 1 \\\\ 0.2 & -0.4 & 0.6 \\\\ 1.4 & 1.6 & 1.8 \\\\ -1 & 1.2 & -1.4 \\end{bmatrix}$$

\\)

Explanation:

Identify the operation and matrix elements

Using the Scalar Multiplication knowledge point

$$ A =
LATEXBLOCK0
, \quad k = 0.2 $$

Multiply each element by the scalar

Using the Scalar Multiplication knowledge point

$$ 0.2 A =
LATEXBLOCK1
=
LATEXBLOCK2
$$

Answer:

• (A) \(

$$\begin{bmatrix} 0.6 & -0.8 & -1 \\ -0.2 & 0.4 & -0.6 \\ -1.4 & -1.6 & -1.8 \\ 1 & -1.2 & 1.4 \end{bmatrix}$$

\)

• **(B) \(

$$\begin{bmatrix} -0.6 & 0.8 & 1 \\ 0.2 & -0.4 & 0.6 \\ 1.4 & 1.6 & 1.8 \\ -1 & 1.2 & -1.4 \end{bmatrix}$$

\) (Correct answer)**