Question

question 19 of 25 if the area of the trapezoid below is 98 square units, what is the value of x? a. 14 units b. 3.5 units c. 7 units d. 1.75 units

Explanation:

Step1: Recall trapezoid area formula

$A=\frac{(b_1 + b_2)h}{2}$, where $b_1$ and $b_2$ are the lengths of the bases and $h$ is the height. Here, $b_1 = 8$, $b_2=20$, $A = 98$, and $h=x$.

Step2: Substitute values into formula

$98=\frac{(8 + 20)x}{2}$

Step3: Simplify the equation

First, simplify the sum in the numerator: $8 + 20=28$. So the equation becomes $98=\frac{28x}{2}$, and $\frac{28x}{2}=14x$. So, $14x = 98$.

Step4: Solve for $x$

Divide both sides of the equation $14x = 98$ by 14: $x=\frac{98}{14}=7$ units.

Answer:

C. 7 units