Question

question 15 of 25
suppose a normal distribution has a mean of 79 and a standard deviation of 7. what is ( p(xgeq72) )?
a. 0.84
b. 0.975
c. 0.16
d. 0.025

Explanation:

Step1: Calculate z-score

$z = \frac{x - \mu}{\sigma} = \frac{72 - 79}{7} = -1$

Step2: Find probability for z=-1

Using standard normal table, $P(Z \geq -1) = 1 - P(Z < -1) = 1 - 0.16 = 0.84$

Answer:

A. 0.84