Question

question 3 of 10
which shows the equation below written in the form ( ax^2 + bx + c = 0 )?
( 2x^2 - 3 = -6x - 2 )

a. ( 2x^2 - 6x - 5 = 0 )
b. ( 2x^2 + 6x - 1 = 0 )
c. ( 2x^2 + 6x - 5 = 0 )
d. ( 2x^2 - 6x - 1 = 0 )

Explanation:

Step1: Move all terms to left side

To write the equation \(2x^2 - 3=-6x - 2\) in the form \(ax^2+bx + c = 0\), we add \(6x\) and \(2\) to both sides.

$$2x^2-3 + 6x+2=-6x - 2+6x + 2$$

Step2: Simplify the equation

Simplify the left - hand side and the right - hand side:
The left - hand side: \(2x^2+6x+( - 3 + 2)=2x^2+6x-1\)
The right - hand side: \(0\)
So the equation in the form \(ax^2+bx + c = 0\) is \(2x^2+6x - 1=0\)

Answer:

B. \(2x^2 + 6x-1 = 0\)