Question

question 10 (1 point)
four different pencils have lengths of 12.45 cm, 11.22 cm, 12.75 cm, and 12.42 cm. what is the average length of the four pencils?
11.99 cm
48.84 cm
12.43 cm
12.21 cm

Explanation:

Step1: Calculate the sum of lengths

Sum \( S=12.45 + 11.22+12.75 + 12.42\)
\(S=(12.45+12.75)+(11.22 + 12.42)=25.2+23.64 = 48.84\)

Step2: Calculate the average

Average \(A=\frac{S}{n}\), where \(n = 4\) (the number of pencils)
\(A=\frac{48.84}{4}=12.21\)

Answer:

12.21 cm