Question

question 3 of 10
this is the equation of a horizontal hyperbola.
\\(\frac{(y - 2)^2}{16}-\frac{(x + 1)^2}{144}=1\\)
a. true
b. false

Explanation:

Step1: Recall hyperbola standard form

The standard form of a horizontal hyperbola is $\frac{(x - h)^2}{a^2}-\frac{(y - k)^2}{b^2}=1$, and for a vertical hyperbola is $\frac{(y - k)^2}{b^2}-\frac{(x - h)^2}{a^2}=1$, where $(h,k)$ is the center.

Step2: Analyze given equation

The given equation is $\frac{(y - 2)^2}{16}-\frac{(x + 1)^2}{144}=1$, which is in the form of a vertical hyperbola.

Answer:

B. False