Question

question 10 of 15 (3 points) | question attempt 1 of 3
complete the parts below.
(a) find the rise, run, and slope given by triangle abc.
rise:
run:
slope:

Explanation:

Step1: Identify coordinates of A, B, C

Assume from the graph: Let's say \( B=(4,0) \), \( C=(5,0) \) (run), \( A=(4,4) \) (so from B to A, rise is \( 4 - 0 = 4 \), run from B to C is \( 5 - 4 = 1 \)). Wait, maybe better to check the vertical and horizontal changes. Let's suppose triangle ABC: B is at (4,0), C is at (5,0) (horizontal change, run), A is at (4,4) (vertical change from B to A is rise). So rise is \( 4 - 0 = 4 \), run is \( 5 - 4 = 1 \), slope is \( \frac{rise}{run}=\frac{4}{1}=4 \). Wait, maybe the graph has B at (4,0), C at (5,0), A at (4,4). So:

Step2: Calculate rise

Rise is vertical change: from B (y=0) to A (y=4), so rise = \( 4 - 0 = 4 \).

Step3: Calculate run

Run is horizontal change: from B (x=4) to C (x=5), so run = \( 5 - 4 = 1 \).

Step4: Calculate slope

Slope = \( \frac{rise}{run}=\frac{4}{1}=4 \).

Answer:

rise: 4, run: 1, slope: 4 (Note: Depending on actual graph coordinates, adjust. If the graph has different points, recalculate. But based on typical slope triangle, this is a common example.)