Question

question 2
(04.02 lc)
solve the system of equations using substitution.
y = -2x + 1
4x + 2y = -3

infinitely many solutions
no solution
(0, -5)
(-5, 0)

Explanation:

Step1: Substitute \( y = -2x + 1 \) into \( 4x + 2y = -3 \)

Substitute \( y \) in the second equation: \( 4x + 2(-2x + 1) = -3 \)

Step2: Simplify the equation

Expand and simplify: \( 4x - 4x + 2 = -3 \) → \( 0x + 2 = -3 \) → \( 2 = -3 \)
This is a contradiction, so the system has no solution.

Answer:

No solution