Question

a quadratic equation has exactly one real number solution. which is the value of its discriminant?
-1
0
1
2

Explanation:

Step1: Recall discriminant rules

For a quadratic equation \(ax^2 + bx + c = 0\) (\(a
eq0\)), the discriminant is \(D = b^2 - 4ac\). The number of real solutions is determined by:

• If \(D>0\): two distinct real solutions.
• If \(D = 0\): one real solution (a repeated root).
• If \(D<0\): no real solutions (two complex conjugate roots).

Step2: Apply to the problem

The problem states the quadratic has exactly one real number solution. From the discriminant rules, this occurs when \(D = 0\).

Answer:

B. 0