QUESTION IMAGE
Question
the proof \\(\delta abc \cong \delta dcb\\) that is shown.
given: \\(\angle a \cong \angle d\\); \\(\overline{cd} \parallel \overline{ab}\\)
prove: \\(\delta abc \cong \delta dcb\\)
what is the missing reason in the proof?
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$$\begin{tabular}{l|l}
statement & reason \\\\
\\hline
1. \\(\\angle a \\cong \\angle d\\) & 1. given \\\\
2. \\(\\overline{cd} \\parallel \\overline{ab}\\) & 2. given \\\\
3. \\(\\overline{cb} \\cong \\overline{bc}\\) & 3. refl. prop. \\\\
4. \\(\\angle abc \\cong \\angle dcb\\) & 4. alt. int. \\(\\angle\\)s are \\(\\cong\\) \\\\
5. \\(\\delta abc \\cong \\delta dcb\\) & 5. ?
\\end{tabular}$$
alt. ext. \\(\angle\\)s are \\(\cong\\)
asa
aas
corr. int. \\(\angle\\)s are \\(\cong\\)
Identify the established congruent parts
Using the Triangle Congruence Proofs knowledge point
- Statement 1: \(\angle A \cong \angle D\) (Angle)
- Statement 3: \(\overline{CB} \cong \overline{BC}\) (Side)
- Statement 4: \(\angle ABC \cong \angle DCB\) (Angle)
Determine the congruence theorem
Using the AAS Congruence Theorem knowledge point
- The congruent parts are two angles and a non-included side: \(\angle A\), \(\angle ABC\), and side \(\overline{BC}\) for \(\triangle ABC\); and \(\angle D\), \(\angle DCB\), and side \(\overline{CB}\) for \(\triangle DCB\).
- Therefore, the triangles are congruent by the Angle-Angle-Side (AAS) congruence theorem.
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