QUESTION IMAGE
Question
problem 24
clear
statements
reasons
given: parallelogram
dfgj, dj > df
- click here to insert
- given
- m∠dfj > m∠djf
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prove: m∠gjf > m∠djf
- (overline{fd}paralleloverline{gj})
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Part 1: Inserting the First Statement
Step1: Identify the Given Information
The first given is "Parallelogram DFGJ, DJ > DF". So the first statement should be "Parallelogram DFGJ, DJ > DF".
Part 2: Reason for \(m\angle DFJ>m\angle DJF\)
Step1: Recall the Isosceles Triangle Theorem (Extended)
In a triangle, if one side is longer than another side, then the angle opposite the longer side is larger. In \(\triangle DFJ\), since \(DJ > DF\), by the side - angle relationship in a triangle (if \(a>b\) in \(\triangle ABC\) where \(a,b\) are side lengths and \(A,B\) are the angles opposite to \(a,b\) respectively, then \(A > B\)), the reason for \(m\angle DFJ>m\angle DJF\) is "In a triangle, the larger side is opposite the larger angle".
Part 3: Reason for \(\overline{FD}\parallel\overline{GJ}\)
Step1: Recall the Property of Parallelograms
One of the properties of a parallelogram is that opposite sides are parallel. Since DFGJ is a parallelogram, \(\overline{FD}\) and \(\overline{GJ}\) are opposite sides. So the reason is "Opposite sides of a parallelogram are parallel".
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- Parallelogram DFGJ, DJ > DF
- In a triangle, the larger side is opposite the larger angle
- Opposite sides of a parallelogram are parallel