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Question
pre - algebra #10
practice: multiply to simplify.
1.) $3(4x) =$
2.) $-5(6a) =$
3.) $(-3)(-2n) =$
4.) $(-3n)(2) =$
5.) $(-2x)(5y) =$
6.) $(-3a)(4b) =$
7.) $-3(7xy) =$
8.) $4(-4ab) =$
9.) $-2(-6rs) =$
10.) $(8xy)(8) =$
11.) $(3bc)(-9d)$
12.) $(-3z)(-2y) =$
13.) $-5(-3a)(-2b) =$
14.) $(3b)(2c)(-4d) =$
Step1: Solve \(3(4x)\)
Using the distributive property \(a(bc)=(ab)c\), multiply 3 and 4 first. \(3\times4 = 12\), so \(3(4x)=12x\).
Step2: Solve \(-5(6a)\)
Multiply -5 and 6. \(-5\times6=-30\), so \(-5(6a)=-30a\).
Step3: Solve \((-3)(-2n)\)
Multiply -3 and -2. \((-3)\times(-2) = 6\), so \((-3)(-2n)=6n\).
Step4: Solve \((-3n)(2)\)
Multiply -3 and 2. \(-3\times2=-6\), so \((-3n)(2)=-6n\).
Step5: Solve \((-2x)(5y)\)
Multiply -2 and 5, and keep the variables. \((-2)\times5=-10\), so \((-2x)(5y)=-10xy\).
Step6: Solve \((-3a)(4b)\)
Multiply -3 and 4, and keep the variables. \(-3\times4=-12\), so \((-3a)(4b)=-12ab\).
Step7: Solve \(-3(7xy)\)
Multiply -3 and 7. \(-3\times7=-21\), so \(-3(7xy)=-21xy\).
Step8: Solve \(4(-4ab)\)
Multiply 4 and -4. \(4\times(-4)=-16\), so \(4(-4ab)=-16ab\).
Step9: Solve \(-2(-6rs)\)
Multiply -2 and -6. \((-2)\times(-6)=12\), so \(-2(-6rs)=12rs\).
Step10: Solve \((8xy)(8)\)
Multiply 8 and 8. \(8\times8 = 64\), so \((8xy)(8)=64xy\).
Step11: Solve \((3bc)(-9d)\)
Multiply 3 and -9, and keep the variables. \(3\times(-9)=-27\), so \((3bc)(-9d)=-27bcd\).
Step12: Solve \((-3z)(-2y)\)
Multiply -3 and -2. \((-3)\times(-2)=6\), so \((-3z)(-2y)=6zy\) (or \(6yz\)).
Step13: Solve \(-5(-3a)(-2b)\)
First multiply -5 and -3: \(-5\times(-3)=15\). Then multiply 15 and -2: \(15\times(-2)=-30\). So \(-5(-3a)(-2b)=-30ab\).
Step14: Solve \((3b)(2c)(-4d)\)
First multiply 3 and 2: \(3\times2 = 6\). Then multiply 6 and -4: \(6\times(-4)=-24\). Keep the variables, so \((3b)(2c)(-4d)=-24bcd\).
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