Question

g.pr.10.1 (mc)

there are 24 marbles in a bag. there are 4 red, 8 blue, 10 green, and 2 yellow marbles. find p(red \cup yellow).

\bigcirc \frac{1}{72}
\bigcirc 0
\bigcirc \frac{1}{4}
\bigcirc \frac{1}{18}

Explanation:

Identify the total outcomes and favorable outcomes

$$
LATEXBLOCK0
$$

Calculate the probability

$$ P(\text{red} \cup \text{yellow}) = \frac{6}{24} = \frac{1}{4} $$

Answer:

• (A) \(\frac{1}{72}\)
• (B) \(0\)
• (C) \(\frac{1}{4}\) (Correct answer)
• (D) \(\frac{1}{18}\)