g.pr.10.2 (lc)

$p(a) = 0.28$ and $p(b) = 0.6$. what is $p(a \cap b)$ if events a and b are independent?

- 0.88
- 0.467
- 0.26
- 0.168

Question

g.pr.10.2 (lc)

$p(a) = 0.28$ and $p(b) = 0.6$. what is $p(a \cap b)$ if events a and b are independent?

- 0.88
- 0.467
- 0.26
- 0.168

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "multiple_choice_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Independent Events", "Probability Formulas" ], "new_concepts": [], "current_concepts": [ "Independent Events", "Probability Formulas" ] } ## Identify the given values and formula for independent events $$ \begin{aligned} P(A) &= 0.28 \ P(B) &= 0.6 \ P(A \cap B) &= P(A) \cdot P(B) \end{aligned} $$ ## Calculate the intersection probability $$ \begin{aligned} P(A \cap B) &= 0.28 \cdot 0.6 \ P(A \cap B) &= 0.168 \end{aligned} $$

0.88

0.467

0.26

0.168

{ "subject": "Mathematics", "question_type": "Multiple Choice", "knowledge_point": [ "Mathematics", "Statistics", "Independent Events" ] }

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Question

Explanation:

Identify the given values and formula for independent events

Calculate the intersection probability

Answer: