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a poll of 1019 americans showed that 47.4% of the respondents prefer to…

Question

a poll of 1019 americans showed that 47.4% of the respondents prefer to watch the news rather than read or listen to it. use these results with a 0.01 significance level to test the claim that fewer than half of americans prefer to watch the news rather than read or listen to it. use the p - value method. use the normal distribution as an approximation to the binomial distribution.
let p denote the population proportion of all americans who prefer to watch the news rather than read or listen to it. identify the null and alternative hypotheses.
$h_0:p$
$h_1:p$
(type integers or decimals. do not round.)

Explanation:

Step1: Set up null hypothesis

The null hypothesis \(H_0\) is a statement of equality. Since the claim is about comparing to half (\(p = 0.5\)), \(H_0:p=0.5\)

Step2: Set up alternative hypothesis

The alternative hypothesis \(H_1\) is the claim we are testing. The claim is "fewer than half", so \(H_1:p < 0.5\)

Answer:

\(H_0:p = 0.5\)
\(H_1:p<0.5\)