Question

(4 points)

1. a student surveyed 100 adults who took either vitamin c, zinc, or echinacea supplements to prevent getting a cold. the adults were asked if they had a cold or no cold in the last 30 days. the results are shown in the table.

a. what percent of adults in the survey took echinacea?

b. what percent of adults who took vitamin c reported having a cold in the last 30 days?

c. what percent of adults who reported having a cold took zinc?

Explanation:

Step1: Calculate the percentage for part a

The formula for percentage is \( \frac{\text{Number of adults who took echinacea}}{\text{Total number of adults}} \times 100\).
From the table, the number of adults who took echinacea is \(27\) and the total number of adults is \(100\).

$$ \frac{27}{100} \times 100 = 27\% $$

Step2: Calculate the percentage for part b

The formula is \( \frac{\text{Number of adults who took vitamin C and had a cold}}{\text{Total number of adults who took vitamin C}} \times 100\).
Number of adults who took vitamin C and had a cold is \(15\), and total number of adults who took vitamin C is \(56\).

$$ \frac{15}{56} \times 100=\frac{1500}{56}\approx 26.79\% $$

Step3: Calculate the percentage for part c

The formula is \( \frac{\text{Number of adults who had a cold and took zinc}}{\text{Total number of adults who had a cold}} \times 100\).
Number of adults who had a cold and took zinc is \(5\), and total number of adults who had a cold is \(26\).

$$ \frac{5}{26} \times 100=\frac{500}{26}\approx 19.23\% $$

Answer:

a. \(27\%\)
b. Approximately \(26.79\%\)
c. Approximately \(19.23\%\)