Question

plot (2, 0), (-5, -2), (-5, 4), and (3, -1).

Explanation:

Step1: Plot (2, 0)

Locate \( x = 2 \) on the x - axis and \( y = 0 \) on the y - axis. The point (2, 0) lies on the x - axis, 2 units to the right of the origin.

Step2: Plot (-5, -2)

Find \( x=-5 \) (5 units to the left of the origin on the x - axis) and \( y = - 2 \) (2 units below the origin on the y - axis). Mark the point at this intersection.

Step3: Plot (-5, 4)

For \( x=-5 \) (same x - coordinate as the previous point) and \( y = 4 \) (4 units above the origin on the y - axis). Mark the point at this (x, y) intersection.

Step4: Plot (3, -1)

Locate \( x = 3 \) (3 units to the right of the origin on the x - axis) and \( y=-1 \) (1 unit below the origin on the y - axis). Mark the point here.

(Note: Since the problem is about plotting points on a coordinate plane, the final answer is the set of plotted points as per the above steps. If we were to describe the plotting process, the key is to correctly identify the x and y coordinates for each point and mark them on the grid.)

Answer:

The points (2, 0), (-5, -2), (-5, 4), and (3, -1) are plotted on the coordinate grid as described in the steps.