Question

the picture below shows a box sliding down a ramp: what is the distance, in feet, that the box has to travel to move from point a to point c? 10 cos 62° $\frac{10}{sin62}$ $\frac{10}{cos62}$ 10 sin 62°

Explanation:

Step1: Identify trigonometric - relation

In right - triangle ABC, $\angle C = 62^{\circ}$, the side opposite $\angle C$ is AB with length 10 ft, and we want to find the hypotenuse AC.
We know that $\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}$.

Step2: Solve for the hypotenuse

If $\sin C=\sin62^{\circ}=\frac{AB}{AC}$, and $AB = 10$ ft. Then $AC=\frac{AB}{\sin62^{\circ}}=\frac{10}{\sin62^{\circ}}$.

Answer:

$\frac{10}{\sin62^{\circ}}$