QUESTION IMAGE
Question
perform the indicated operation. write the answer in the form $a + bi$.
$(3 - 2i)^2=square$
Step1: Expand using formula
Use the formula $(a - b)^2=a^{2}-2ab + b^{2}$, where $a = 3$ and $b = 2i$. So, $(3 - 2i)^2=3^{2}-2\times3\times2i+(2i)^{2}$.
Step2: Calculate each term
$3^{2}=9$, $2\times3\times2i = 12i$, and $(2i)^{2}=4i^{2}$. Since $i^{2}=-1$, then $4i^{2}=-4$.
Step3: Combine terms
$9-12i-4=(9 - 4)-12i=5-12i$.
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$5-12i$