Question

1. a particular airline offers three free snack options to its passengers: cookies, chips, and crackers. along with the snack, passengers are offered two free drink options: soda or water.

this is a tree diagram that represents the probability of customers choosing the different snack and drink options.

tree diagram image: first branch cookies (.3), then splits to soda (.5) and water (.5); second branch chips (.5), splits to soda (.5) and water (.5); third branch crackers z, splits to soda (.5) and water (.5)

what is the probability of a passenger choosing either a soda or water with cookies?

○ 30%
○ 80%

Explanation:

Step1: Identify cookie probability

Probability of cookies: $0.3$

Step2: Soda or water with cookies

Soda and water with cookies are mutually exclusive, so sum their probabilities. But since soda (0.5) and water (0.5) with cookies: total for cookies' drinks is $0.5 + 0.5 = 1$. Then multiply by cookie probability? Wait, no—wait, the question is "either soda or water with cookies". Since choosing soda or water with cookies means choosing cookies (0.3) and then either drink. But the drinks with cookies are soda (0.5) or water (0.5), so the total probability for cookies and (soda or water) is 0.3 (0.5 + 0.5) = 0.3 1 = 0.3, which is 30%.

Answer:

30%