Question

part 1 of 3
suppose that y is inversely proportional to square of x.
find the constant of proportionality k if y = 11 when x = 6.
k = 396
part 2 of 3
using the k from above write the variation equation in terms of x.
y = \frac{396}{x^2}
part 3 of 3
using the k from above find y given that x = 35.
y =
if needed, round answer to 3 decimal places.
enter dne for does not exist, \infty for infinity
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Explanation:

Step1: Use the variation equation

We use the equation $y = \frac{396}{x^2}$ from Part 2.

Step2: Substitute x = 35

Substitute $x=35$ into the equation:
$y = \frac{396}{35^2}$

Step3: Calculate denominator and simplify

First compute $35^2 = 1225$, then:
$y = \frac{396}{1225} \approx 0.323$

Answer:

0.323