Question

part iv: if each of the quadrilateral below is a square, give the me
1
2
vu=
su=
tv=
sw=
2

Explanation:

Step1: Properties of a square

In a square, all sides are equal. So, \( VU = 15 \) (since each side of the square is equal and \( TU = 15 \)).

Step2: Diagonals of a square

The diagonals of a square are equal. Using the Pythagorean theorem for right - triangle \( TUV \) (where \( TV \) and \( SU \) are diagonals and \( \angle{VUT}=90^{\circ}\), \( TV = SU=\sqrt{15^{2}+15^{2}}=\sqrt{225 + 225}=\sqrt{450}=15\sqrt{2}\)

Step3: Mid - point of the diagonal

The diagonals of a square bisect each other. So, \( SW=\frac{1}{2}SU\). Since \( SU = 15\sqrt{2}\), then \( SW=\frac{15\sqrt{2}}{2}\)

Answer:

\( VU = 15\), \( SU=15\sqrt{2}\), \( TV = 15\sqrt{2}\), \( SW=\frac{15\sqrt{2}}{2}\)