Question

part 3: iteration race
you need a password generator that produces 5 random characters.
task a: write pseudocode using a loop that repeats exactly 5 times:
handwritten text omitted
task b: how would you change the loop if the number of characters was chosen by the user instead of fixed at 5?

part 4: logic gate puzzle
look at this logic circuit: (a and b) or c
task a: fill in the truth table.

a b c (a and b) output ((a and b) or c)
0 0
0 1
1 0
1 1
0 0
0 1
1 0
1 1

Explanation:

Part 3: Iteration Race

Task A: Pseudocode for Fixed 5 Characters

Step1: Initialize loop counter

Set counter = 1

Step2: Start loop with condition

While counter <= 5

Step3: Generate random character (pseudocode for generation)

Generate a random character (e.g., random_char = generate_random_character())

Step4: Output or store the character

Print random_char (or add to password string)

Step5: Increment counter

Set counter = counter + 1
End While

Step1: Get user input for character count

Get n from user (e.g., n = input("Enter number of characters: "))

Step2: Initialize loop counter

Set counter = 1

Step3: Start loop with condition using user input

While counter <= n

Step4: Generate random character

Generate a random character (e.g., random_char = generate_random_character())

Step5: Output or store the character

Print random_char (or add to password string)

Step6: Increment counter

Set counter = counter + 1
End While

(for Truth Table filling):

Step1: Evaluate (A AND B)

For each row, use the AND rule: if A = 1 and B = 1, (A AND B)=1, else 0.

Step2: Evaluate (A AND B) OR C

For each row, use the OR rule: if either (A AND B) is 1 or C is 1, output is 1, else 0.

Answer:

counter = 1
WHILE counter <= 5 DO
    random_char = generate_random_character()
    PRINT random_char
    counter = counter + 1
END WHILE

Task B: User - Defined Number of Characters