Question

a parachutist’s rate during a free fall reaches 231 feet per second. what is this rate in meters per second? at this rate, how many meters will the parachutist fall during 2 seconds of free fall? in your computations, assume that 1 meter is equal to 3.3 feet. do not round your answers.

Explanation:

Step1: Convert feet per second to meters per second

We know that 1 meter = 3.3 feet, so to convert 231 feet per second to meters per second, we divide by 3.3. So the rate \( r=\frac{231}{3.3}\) m/s. Calculating that, \( \frac{231}{3.3} = 70\) m/s.

Step2: Calculate distance fallen in 2 seconds

The formula for distance \( d\) with constant rate \( r\) and time \( t\) is \( d = r\times t\). Here, \( r = 70\) m/s and \( t = 2\) s. So \( d=70\times2=140\) meters.

Answer:

Rate: \( 70\) \(\frac{\text{m}}{\text{s}}\)
Distance fallen in 2 seconds: \( 140\) m