Question

in order to get one digit to the left of the decimal point, it needs to be shifted -8 places to the right. this indicates that we need a negative exponent. submit skip (you cannot come back)

Explanation:

To solve this problem, we analyze the context of decimal place shifting and exponents:

Step 1: Understand Decimal Shifting

When we want a digit to the left of the decimal point, a negative exponent indicates shifting the decimal to the right (since a negative exponent in scientific notation, like \(10^{-n}\), means dividing by \(10^n\), which shifts the decimal \(n\) places right). For example, \(0.00000001 = 1 \times 10^{-8}\), where the decimal shifts 8 places right to get from \(1.0\) to \(0.00000001\).

Step 2: Confirm the Terms

• The first blank (for the exponent type) is "negative" because a negative exponent corresponds to shifting right (or dividing by powers of 10).
• The second blank (for the direction of shift) is "right" because a negative exponent in \(10^{-8}\) means shifting the decimal 8 places to the right to represent a very small number.

Answer:

First blank: negative
Second blank: right