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Question
opposite side/hypotenuse =
Step1: Apply Pythagorean theorem
$$\begin{align*}
AB^{2}&=BC^{2}+AC^{2}\\
AB^{2}&=(\sqrt{3})^{2}+(\sqrt{13})^{2}\\
AB^{2}&=3 + 13\\
AB^{2}&=16\\
AB& = 4
\end{align*}$$
Step2: Calculate the ratio
The opposite side to angle \(A\) is \(BC=\sqrt{3}\), and the hypotenuse \(AB = 4\). So \(\frac{\text{OPPOSITE SIDE}}{\text{HYPOTENUSE}}=\frac{BC}{AB}\)
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\(\frac{\sqrt{3}}{4}\)