Question

one spring day, john noted the time of day and the temperature, in degrees fahrenheit. during that time, the temperature rose, stayed steady, and fell, at different rates. on the set of axes below, john created a graph of temperature over time. at what rate did the temperature rise from 9 a.m. to 1 p.m.?

Explanation:

Step1: Identify time - interval

The time interval from 9 a.m. to 1 p.m. is $13 - 9=4$ hours.

Step2: Identify temperature - change

From the graph, at 9 a.m. the temperature is approximately 55°F and at 1 p.m. the temperature is approximately 72°F. The temperature change is $72 - 55 = 17$°F.

Step3: Calculate rate of change

The rate of change of temperature (slope) is given by the formula $\text{Rate}=\frac{\text{Change in Temperature}}{\text{Change in Time}}$. So, $\text{Rate}=\frac{17}{4}= 4.25$°F per hour.

Answer:

$4.25$°F per hour