Question

an object is launched from a platform. its height (in meters), x seconds after the launch, is modeled by: h(x) = -5x² + 20x + 60 what is the height of the object at the time of launch? meters

Explanation:

Step1: Determine time at launch

At launch, the time \( x = 0 \) seconds.

Step2: Substitute \( x = 0 \) into \( h(x) \)

Substitute \( x = 0 \) into \( h(x)=-5x^{2}+20x + 60 \):
\( h(0)=-5(0)^{2}+20(0)+60 \)
\( h(0)=0 + 0+60=60 \)

Answer:

60