Question

number x frequency f relative frequency f/n
0
1 7 23%
2 6 20%
3
4 3 10%
5 1 3%
data table
full data set
0 3 1 0 2 1 5 2 0 4
1 0 3 1 0 2 1 4 2 0
3 1 0 3 1 0 2 0 4 2
print done

Explanation:

Step1: Calculate total number of data points

Count the number of data points in the full data set. There are \(30\) data points (\(n = 30\)).

Step2: Calculate frequency for \(x = 0\)

Since relative frequency of \(x = 1\) is \(23\%=\frac{7}{n}\), and \(n = 30\).
The number of \(0\)'s:
Let the frequency of \(x = 0\) be \(f_0\).
We know that \(\sum f=n\).
\(f_0+7 + 6+f_3+3 + 1=30\)
\(f_0+f_3=30-(7 + 6+3 + 1)=13\)
Count the number of \(0\)'s in the data set: there are \(7\) \(0\)'s.

Step3: Calculate relative frequency for \(x = 0\)

Relative frequency of \(x = 0\): \(\frac{7}{30}\times100\%\approx23\%\)

Step4: Calculate frequency for \(x = 3\)

Since \(n = 30\), and \(f_0 = 7\), \(f_1=7\), \(f_2 = 6\), \(f_4=3\), \(f_5 = 1\)
\(f_3=30-(7 + 7+6 + 3+1)=6\)

Step5: Calculate relative frequency for \(x = 3\)

Relative frequency of \(x = 3\): \(\frac{6}{30}\times 100\%=20\%\)

Answer:

Number \(x\)	Frequency \(f\)	Relative Frequency \(\frac{f}{n}\)
\(1\)	\(7\)	\(23\%\)
\(2\)	\(6\)	\(20\%\)
\(3\)	\(6\)	\(20\%\)
\(4\)	\(3\)	\(10\%\)
\(5\)	\(1\)	\(3\%\)