QUESTION IMAGE
Question
- noah is solving the equation below. find the value of x that makes the equation true.
\\(\frac{1}{4}x - 8 = \frac{1}{8}x + 8\\)
Step1: Subtract $\frac{1}{8}x$ from both sides
To eliminate the $\frac{1}{8}x$ term on the right, we subtract $\frac{1}{8}x$ from both sides.
$\frac{1}{4}x - \frac{1}{8}x - 8 = \frac{1}{8}x - \frac{1}{8}x + 8$
Simplifying the $x$ terms: $\frac{2}{8}x - \frac{1}{8}x = \frac{1}{8}x$, so we get $\frac{1}{8}x - 8 = 8$
Step2: Add 8 to both sides
To isolate the term with $x$, we add 8 to both sides.
$\frac{1}{8}x - 8 + 8 = 8 + 8$
Simplifying both sides: $\frac{1}{8}x = 16$
Step3: Multiply both sides by 8
To solve for $x$, we multiply both sides by 8.
$8\times\frac{1}{8}x = 16\times8$
Simplifying: $x = 128$
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$x = 128$