Question

name
whats the product? complete the equation.

1. $5 \times 6,000 = 5 \times 6 \times \underline{\quad}$

$\quad\quad\quad\quad\quad = \underline{\quad} \times \underline{\quad}$
$\quad\quad\quad\quad\quad = \underline{\quad}$
$8 \times 300 = \underline{\quad} \times 3 \times 100$
$\quad\quad\quad\quad\quad = \underline{\quad} \times \underline{\quad}$
$\quad\quad\quad\quad\quad = \underline{\quad}$

Explanation:

Problem 1:

Step1: Decompose 6,000

Since \( 6,000 = 6\times1,000 \), so the first blank is \( 1,000 \).
\( 5\times6,000 = 5\times6\times1,000 \)

Step2: Multiply 5 and 6

Calculate \( 5\times6 = 30 \).
\( = 30\times1,000 \)

Step3: Multiply 30 and 1,000

Calculate \( 30\times1,000 = 30,000 \).
\( = 30,000 \)

Problem 2:

Step1: Decompose 300

Since \( 300 = 3\times100 \), and the original number is 8, so the first blank is \( 8 \).
\( 8\times300 = 8\times3\times100 \)

Step2: Multiply 8 and 3

Calculate \( 8\times3 = 24 \).
\( = 24\times100 \)

Step3: Multiply 24 and 100

Calculate \( 24\times100 = 2,400 \).
\( = 2,400 \)

Problem (Partially Visible, Assuming the Pattern):

For \( 7\times40 = 7\times\underline{}\times10 \), we know \( 40 = 4\times10 \), so the blank is \( 4 \). Then \( 7\times40 = 7\times4\times10 = 28\times10 = 280 \). But since the problem is partially visible, we focus on the given parts.

Answer:

s:

1. First blank: \( 1,000 \); Second blank: \( 30 \); Third blank: \( 1,000 \); Final result: \( 30,000 \)
2. First blank: \( 8 \); Second blank: \( 24 \); Third blank: \( 100 \); Final result: \( 2,400 \)

(For the partially visible problem, if we consider \( 7\times40 = 7\times\underline{}\times10 \), the blank is \( 4 \))