Question

name: thor cp algebra 2 date: two way tables classwork 1) coaches and players were asked whether they liked football or baseball the best. complete the 2 - way frequency table. how many people participated in the survey? how many coaches participated in the survey? how many players participated in the survey? which sport is more popular among the coaches? which sport is more popular among the players? 2) fifty students in the 9th grade class were asked what kind of ice cream and toppings they like. create 3 relative frequency tables for the data. write the relative frequencies as a percent. table 1: base it on total people.

Explanation:

Step1: Calculate the total number of people in the first table

The total number of people is the sum of all the individual cells. We can also use the total row and column. The total number of people is \(12 + 12=24\) (since the total of coaches and players).

Step2: Find the number of coaches

The number of coaches is given by the sum of coaches who like football and baseball. So \(5 + 7=12\)

Step3: Find the number of players

The number of players is given by the sum of players who like football and baseball. So \(12- 5=7\) (using the football column total) or \(6 + 6=12\) (sum of players' row)

Step4: Determine the more popular sport among coaches

Compare the number of coaches who like football (\(5\)) and baseball (\(7\)). Since \(7>5\), baseball is more popular among coaches.

Step5: Determine the more popular sport among players

Compare the number of players who like football (\(7\)) and baseball (\(6\)). Since \(7>6\), football is more popular among players.

For the second part (relative - frequency table based on total people):

The formula for relative frequency (as a percentage) is \(\text{Relative Frequency}=\frac{\text{Frequency}}{\text{Total}}\times100\%\)

For Vanilla - Sprinkles:

\(\frac{9}{50}\times100\% = 18\%\)

For Vanilla - m&m's:

\(\frac{8}{50}\times100\%=16\%\)

For Vanilla - Nothing:

\(\frac{13}{50}\times100\% = 26\%\)

For Vanilla - Total:

\(\frac{30}{50}\times100\%=60\%\)

For Chocolate - Sprinkles:

\(\frac{7}{50}\times100\% = 14\%\)

For Chocolate - m&m's:

\(\frac{9}{50}\times100\%=18\%\)

For Chocolate - Nothing:

\(\frac{4}{50}\times100\% = 8\%\)

For Chocolate - Total:

\(\frac{20}{50}\times100\%=40\%\)

For Total - Sprinkles:

\(\frac{16}{50}\times100\%=32\%\)

For Total - m&m's:

\(\frac{17}{50}\times100\% = 34\%\)

For Total - Nothing:

\(\frac{17}{50}\times100\%=34\%\)

For Total - Total:

\(\frac{50}{50}\times100\% = 100\%\)

Answer:

• Number of people in the first survey: \(24\)
• Number of coaches: \(12\)
• Number of players: \(12\)
• More popular sport among coaches: Baseball
• More popular sport among players: Football

For the relative - frequency table (Table 1):

	Sprinkles	m & m's	Nothing	Total
Chocolate	\(14\%\)	\(18\%\)	\(8\%\)	\(40\%\)
Total	\(32\%\)	\(34\%\)	\(34\%\)	\(100\%\)