QUESTION IMAGE
Question
name
date
period
geometry
unit 2: logic & proof
quiz 2.1: statements, compound, and conditionals
determine if the conjecture below are true or false. if false, give a counterexample.
1.
4.
8.
match each statement with its symbolic notation.
- conjunction a. ( q \to p )
b. disjunction b. ( p leftrightarrow q )
- conditional c. ( p vee q )
- biconditional d. (
eg p \to
eg q )
- contrapositive e. (
eg q \to
eg p )
- converse f. ( p wedge q )
- inverse g. ( p \to q )
use the statements below to write compound statements. then, determine the truth value.
p: atlanta is the capital of georgia.
q: there are 4 feet in a yard.
- ( p vee q ):
truth value:
- ( p wedge q ):
truth value:
- ( p wedge
eg q ):
truth value:
- (
eg p vee q ):
truth value:
© gina wilson (all things algebra), llc), 2014 - 2018
Step1: Analyze statement \( p \) and \( q \)
- \( p \): Atlanta is the capital of Georgia (True, as Atlanta is the capital of Georgia).
- \( q \): There are 4 feet in a yard (False, as there are 3 feet in a yard, so \(
eg q \) is True).
Step2: Solve \( p \vee q \)
- \( p \vee q \) means "Atlanta is the capital of Georgia or there are 4 feet in a yard".
- In logic, a disjunction (\( \vee \)) is true if at least one of the statements is true. Since \( p \) is true, \( p \vee q \) is true.
Step3: Solve \( p \wedge q \)
- \( p \wedge q \) means "Atlanta is the capital of Georgia and there are 4 feet in a yard".
- A conjunction (\( \wedge \)) is true only if both statements are true. Since \( q \) is false, \( p \wedge q \) is false.
Step4: Solve \( p \wedge
eg q \)
- \(
eg q \) is "There are not 4 feet in a yard" (which is true).
- \( p \wedge
eg q \) means "Atlanta is the capital of Georgia and there are not 4 feet in a yard".
- Both \( p \) and \(
eg q \) are true, so the conjunction is true.
Step5: Solve \(
eg p \vee q \)
- \(
eg p \) is "Atlanta is not the capital of Georgia" (false).
- \(
eg p \vee q \) means "Atlanta is not the capital of Georgia or there are 4 feet in a yard".
- A disjunction is true if at least one is true, but both \(
eg p \) and \( q \) are false, so \(
eg p \vee q \) is false.
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s:
- \( p \vee q \): Atlanta is the capital of Georgia or there are 4 feet in a yard; Truth Value: True
- \( p \wedge q \): Atlanta is the capital of Georgia and there are 4 feet in a yard; Truth Value: False
- \( p \wedge
eg q \): Atlanta is the capital of Georgia and there are not 4 feet in a yard; Truth Value: True
- \(
eg p \vee q \): Atlanta is not the capital of Georgia or there are 4 feet in a yard; Truth Value: False