QUESTION IMAGE
Question
multiply and simplify.
\\((4 - 6\sqrt{5})(3 + 3\sqrt{5})\\)
\\((4 - 6\sqrt{5})(3 + 3\sqrt{5}) = \square\\)
(type an exact answer, using radicals as needed.)
⚡ Using what you learned: Roots and Radicals
Step 1: Expand the expression
Apply the FOIL method to multiply the two binomials:
$$
(4 - 6\sqrt{5})(3 + 3\sqrt{5}) = (4)(3) + (4)(3\sqrt{5}) - (6\sqrt{5})(3) - (6\sqrt{5})(3\sqrt{5})
$$
Step 2: Multiply individual terms
Calculate each product:
$$
(4)(3) = 12
$$
$$
(4)(3\sqrt{5}) = 12\sqrt{5}
$$
$$
-(6\sqrt{5})(3) = -18\sqrt{5}
$$
$$
-(6\sqrt{5})(3\sqrt{5}) = -18 \cdot 5 = -90
$$
Substitute these values back into the expression:
$$
12 + 12\sqrt{5} - 18\sqrt{5} - 90
$$
Step 3: Combine like terms
Combine the integer terms and the radical terms:
$$
(12 - 90) + (12\sqrt{5} - 18\sqrt{5})
$$
$$
-78 - 6\sqrt{5}
$$
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$$
-78 - 6\sqrt{5}
$$