QUESTION IMAGE
Question
multiply.
$(2y^2 - 6y + 7)(2y^2 + 4y - 5)$
simplify your answer.
Step1: Apply distributive property (FOIL for polynomials)
Multiply each term in the first polynomial by each term in the second polynomial:
$$
LATEXBLOCK0
$$
Step2: Simplify each product
Calculate each term:
$$
LATEXBLOCK1
$$
Step3: Combine like terms
Combine the terms with the same power of \(y\):
- For \(y^4\): \(4y^4\)
- For \(y^3\): \(8y^3 - 12y^3 = -4y^3\)
- For \(y^2\): \(-10y^2 - 24y^2 + 14y^2 = -20y^2\)
- For \(y\): \(30y + 28y = 58y\)
- Constant term: \(-35\)
So the simplified form is:
$$
4y^4 - 4y^3 - 20y^2 + 58y - 35
$$
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\(4y^4 - 4y^3 - 20y^2 + 58y - 35\)