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Question
4 multiple choice 4 points
determine the margin of error.
it has been determined with 95% confidence that the proportion of on - line students at spc who live in pinellas county is between 0.73 and 0.77.
determine the margin of error associated with this confidence interval.
±0.01
±0.02
±0.03
±0.04
±0.05
Step1: Recall the formula for margin of error in confidence interval for proportion
The confidence interval for proportion is given by $\hat{p}-E
Step2: Calculate the width of the given confidence interval
The lower limit $L = 0.73$ and the upper limit $U=0.77$. The width of the confidence interval $W=U - L$. So, $W=0.77-0.73=0.04$.
Step3: Solve for the margin of error $E$
Since $W = 2E$, then $E=\frac{W}{2}$. Substituting $W = 0.04$ into the formula, we get $E=\frac{0.04}{2}=0.02$.
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$\pm0.02$