Question

mrs. novak is teaching a 5th grade class. she is standing 8 meters in front of kristen. baldwin is sitting 6 meters to kristens right. how far apart are mrs. novak and baldwin? meters

Explanation:

Step1: Recognize the right - triangle

The positions of Mrs. Novak, Kristen, and Baldwin form a right - triangle. The distance from Mrs. Novak to Kristen (\(a = 8\) meters) and the distance from Kristen to Baldwin (\(b=6\) meters) are the two legs of the right - triangle. Let the distance from Mrs. Novak to Baldwin be \(c\).

Step2: Apply the Pythagorean theorem

The Pythagorean theorem is \(a^{2}+b^{2}=c^{2}\). Substitute \(a = 8\) and \(b = 6\) into the formula:

$$
LATEXBLOCK0
$$

Step3: Solve for \(c\)

Take the square root of both sides. Since \(c>0\) (distance cannot be negative), \(c=\sqrt{100}=10\)

Answer:

10