Question

the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer. match each function on the left to all points on the right that would be located on the graph of the function. f(x) = 2x - 5; (5, 5); f(x) = 2x² - 8x + 7; (1, 1); f(x) = 2√(x - 4) + 1; (1, -3); (4, 1); clear; click and hold an item in one column, then drag it to the matching item in the other column. be sure your cursor is over the target before releasing. the target will highlight or the cursor will change. need help? watch a video or add

Explanation:

Step 1: Check \( f(x) = 2x - 5 \)

For a point \((x, y)\) to be on the graph, \( y = 2x - 5 \).

• For \((1, -3)\): \( 2(1) - 5 = 2 - 5 = -3 \). So, \((1, -3)\) is on the graph.
• For \((5, 5)\): \( 2(5) - 5 = 10 - 5 = 5 \). So, \((5, 5)\) is on the graph.

Step 2: Check \( f(x) = 2x^2 - 8x + 7 \)

Substitute \( x = 1 \):
\( 2(1)^2 - 8(1) + 7 = 2 - 8 + 7 = 1 \). So, \((1, 1)\) is on the graph.

Step 3: Check \( f(x) = 2\sqrt{x - 4} + 1 \)

Substitute \( x = 4 \):
\( 2\sqrt{4 - 4} + 1 = 2(0) + 1 = 1 \). So, \((4, 1)\) is on the graph.
(For \( x = 1 \), the square root of a negative number is undefined, so \((1, -3)\) and \((1, 1)\) are not on this graph.)

Answer:

• \( f(x) = 2x - 5 \): \((1, -3)\), \((5, 5)\)
• \( f(x) = 2x^2 - 8x + 7 \): \((1, 1)\)
• \( f(x) = 2\sqrt{x - 4} + 1 \): \((4, 1)\)