Question

the minimum of the data is
the first quartile is
the median of the data is
the third quartile is
the maximum of the data is
done
weight of female dogs (lb.)

Explanation:

Step1: Write out the data

The data from the stem - and - leaf plot: \(40,41,43,50,58,61,62,63,65,78,97\)

Step2: Find the minimum

The minimum is the smallest value. So, the minimum is \(40\)

Step3: Find the first quartile (\(Q_1\))

The formula for the position of \(Q_1\) is \(\frac{n + 1}{4}\) where \(n=11\). \(\frac{11+1}{4}=3\). The 3rd value in the ordered data set is \(43\)

Step4: Find the median

The formula for the position of the median is \(\frac{n + 1}{2}\) where \(n = 11\). \(\frac{11+1}{2}=6\). The 6th value in the ordered data set is \(61\)

Step5: Find the third quartile (\(Q_3\))

The formula for the position of \(Q_3\) is \(\frac{3(n + 1)}{4}\) where \(n=11\). \(\frac{3(11 + 1)}{4}=9\). The 9th value in the ordered data set is \(65\)

Step6: Find the maximum

The maximum is the largest value. So, the maximum is \(97\)

Answer:

The minimum of the data is \(40\). The first quartile is \(43\). The median of the data is \(61\). The third quartile is \(65\). The maximum of the data is \(97\)