Question

the means and mean absolute deviations of the individual times of members on two 4×400 - meter relay track teams are shown in the table.
what is the ratio of the difference in the means of the two teams to the mean absolute deviation of team b?
0.09 0.25 0.15 0.65

Explanation:

Step1: Calculate the difference in means

The mean of Team A is \(59.32\) s and the mean of Team B is \(59.1\) s.
The difference in means is \(59.32 - 59.1=0.22\) s.

Step2: Calculate the ratio

The mean absolute deviation of Team B is \(2.4\) s.
The ratio is \(\frac{0.22}{2.4}\approx0.09\).

Answer:

\(0.09\)