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the mean of evelyns scores was 138. complete the chart to find the dist…

Question

the mean of evelyns scores was 138. complete the chart to find the distances from the mean for each of evelyns scores. evelyns scores 125 137 138 145 145 distance from the mean x y 0 7 z x = y = z =

Explanation:

Step1: Calculate the distance for \(x\)

The distance from the mean is calculated as \(| \text{score}-\text{mean}|\). For the score \(125\) and mean \(138\), we have \(|125 - 138|\).

$$|125-138|=| - 13| = 13$$

Step2: Calculate the distance for \(y\)

For the score \(137\) and mean \(138\), we calculate \(|137 - 138|\).

$$|137-138|=| - 1| = 1$$

Step3: Calculate the distance for \(z\)

For the score \(145\) (the second \(145\)) and mean \(138\), we calculate \(|145 - 138|\).

$$|145-138|=7$$

Answer:

\(x = 13\), \(y = 1\), \(z = 7\)