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Question
solve $9 + 4y = -5x + 7y$ for $x$.
$x = \square$
Step1: Isolate terms with x
Subtract \(7y\) and add \(5x\) to both sides: \(9 + 4y - 7y + 5x = -5x + 7y - 7y + 5x\) simplifies to \(9 - 3y + 5x = 0\).
Step2: Solve for x
Subtract \(9 - 3y\) from both sides: \(5x = 3y - 9\). Then divide by 5: \(x = \frac{3y - 9}{5}\) or \(x = \frac{3y}{5} - \frac{9}{5}\).
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\(\frac{3y - 9}{5}\) (or \(\frac{3y}{5} - \frac{9}{5}\))