Question

simplify.
\\(\frac{30k^2 + 6k}{5k + k}\\)
a \\(k + 1\\)
b \\(5k + 1\\)
c \\(6k + 1\\)
d \\(6k + 6\\)

Explanation:

Step1: Simplify Numerator and Denominator

First, factor the numerator \(30k^2 + 6k\). We can factor out \(6k\) from the numerator: \(30k^2 + 6k = 6k(5k + 1)\).
Then, simplify the denominator \(5k + k\). Combine like terms: \(5k + k = 6k\).

Step2: Cancel Common Factors

Now, we have the fraction \(\frac{6k(5k + 1)}{6k}\). The \(6k\) in the numerator and the \(6k\) in the denominator cancel out (assuming \(k
eq 0\) to avoid division by zero), leaving us with \(5k + 1\).

Answer:

B. \(5k + 1\)