Question

m∠e = \boxed{\circ}
m∠f = \boxed{\circ}

Explanation:

Step1: Use the property of cyclic quadrilaterals

In a cyclic quadrilateral, the sum of opposite angles is \(180^{\circ}\).
For \(\angle E\) and \(\angle D\):
\(m\angle E + m\angle D=180^{\circ}\)
Given \(m\angle D = 74^{\circ}\), then \(m\angle E=180^{\circ}-74^{\circ}\)
\(m\angle E = 106^{\circ}\)

Step2: Use the property of cyclic quadrilaterals for \(\angle F\) and \(\angle G\)

\(m\angle F + m\angle G=180^{\circ}\)
Given \(m\angle G = 104^{\circ}\), then \(m\angle F=180^{\circ}-104^{\circ}\)
\(m\angle F = 76^{\circ}\)

Answer:

\(m\angle E = 106^{\circ}\), \(m\angle F = 76^{\circ}\)