Question

evaluate.
$(-9)^2 = \square$
$(-6)^3 = \square$

Explanation:

Step1: Evaluate \((-9)^2\)

Recall that \((-a)^n = a^n\) when \(n\) is even. Here, \(n = 2\) (even) and \(a = 9\). So \((-9)^2=(-9)\times(-9)=81\).

Step2: Evaluate \((-6)^3\)

Recall that \((-a)^n=-a^n\) when \(n\) is odd. Here, \(n = 3\) (odd) and \(a = 6\). So \((-6)^3=(-6)\times(-6)\times(-6)=36\times(-6)= - 216\).

Answer:

For \((-9)^2\), the answer is \(81\); for \((-6)^3\), the answer is \(-216\)