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9. if $overline{lk}congoverline{mk}$, $lk = 7x - 10$, $kn=x + 3$, $mn=9…

Question

  1. if $overline{lk}congoverline{mk}$, $lk = 7x - 10$, $kn=x + 3$, $mn=9x - 11$, and $kj = 28$, find $lj$.

Explanation:

Step1: Use congruent - segment property

Since $\overline{LK}\cong\overline{MK}$, then $LK = MK$. Also, $MK=MN - KN$. So we set up the equation $7x - 10=(9x - 11)-(x + 3)$.

Step2: Simplify the right - hand side of the equation

Simplify $(9x - 11)-(x + 3)$:

$$ LATEXBLOCK0 $$

So the equation becomes $7x - 10 = 8x-14$.

Step3: Solve for $x$

Subtract $7x$ from both sides: $- 10=x - 14$.
Add 14 to both sides: $x = 4$.

Step4: Find $LK$

Substitute $x = 4$ into the expression for $LK$: $LK=7x - 10=7\times4 - 10=28 - 10 = 18$.

Step5: Calculate $LJ$

Since $LJ=LK + KJ$, and $LK = 18$ and $KJ = 28$, then $LJ=18 + 28=46$.

Answer:

$46$